In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 exams that are worth 100 points each. A student has received homework scores of 7, 8, 7, 5, and 8 and the first two exam scores are 81 and 80. Assuming that grades are assigned according to the standard scale, where if the grade percentage is 0.9 or higher the student will get an A, and if the grade percentage is between 0.8 and 0.9 the student will get a B, and there are no weights assigned to any of the grades, is it possible for the student to receive an A in the class? What is the minimum score on the third exam that will give an A? What about a B? [8

1. It is not possible, so the student cannot make an A, since he cannot make 119 scores in the third test.

2. Minimum score to make an A in the test is 315 - (35 + 161) = 119

3. The student can make a B, if he can score 84 and above in the third test.

Step-by-step explanation:

1. To get an A, a student must score 90% (0.9) and above

≥ 90% of 350 ≥ 315 scores,

Total Scores in the homework = 35 ((7 x 2) + (8 x 2) + 5) or 70% (35/50)

Total Scores in the two tests = 161 (81 + 80) or 80.5% (161/200)

Total scores by the student in homework and the two tests so far  = 196 (35 + 161).

However, he needs to score 315 (350 x 90%) to make an A.

Therefore, he is short by 119 (350 - 196), he cannot make an A.

2. To get a B, the student must score ≥ 80% or < 90%,

ideally, the student must score 280 (80% of 350) or above.

He would need to score 84 (280 - 196) in the third test to make 280 scores or 80% average of the total.

Therefore, he can make a B if he can score 84 in the third test.

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step-by-step explanation:

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

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