a canoe in still water travels at a rate of 12 miles per hour. the current today is traveling at a rate of 2 miles per hour. if it took an extra hour to travel upstream, how far was the trip one way?

  60 miles

Step-by-step explanation:

We assume the trip is "d" miles and that the "extra hour" refers to the additional time that a current of 2 mph would add. That is, we assume the reference time is for a current of 0 mph.

The time with no current is ...

  time1 = distance/speed

  time1 = d/12 . . . . hours

With a current of 2 mph in the opposite direction, the time is ...

  time2 = d/(12 -2) = d/10

The second time is 1 hour longer than the first, so we have ...

  time2 = 1 + time1

  d/10 = 1 + d/12

  6d = 60 + 5d . . . . multiply by 60

  d = 60 . . . . . . . . . subtract 5d

The one-way distance is 60 miles.

5x+10 is the correct one

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