Which shows a perfect square trinomial? 50y^2-4x^2 100-36x^2y^2 16x^2+24xy+9y^2 49x^2-70xy+10y^2 ~ please answer, i will mark brainliest ~

C

Step-by-step explanation:

the answer is c, hope this helped :)

3. 16x^2+24xy+9y^2

Step-by-step explanation:

A perfect square trinomial has the form of:

a^2+2ab+b^2= (a+b)^2

Let's see which of the given is equivalent to perfect square

1. 50y^2-4x^2

No, this is not a trinomial

2. 100-36x^2y^2

No, this is not a trinomial

3. 16x^2+24xy+9y^2 = (4x)^2 + 2*4x*3y+ (3y)^2 = (4x+3y)^2

Yes, this is a perfect square

4. 49x^2-70xy+10y^2= (7x)^2- 2*7x*10y + 10y^2

No, this is a trinomial but not a perfect square because 10y^2 is not equal to (10y)^2

As per above, the answer is the 3rd choice

d

step-by-step explanation:

d

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.