Here is a circle, centre O, and the tangent to the circle at the point (8, 15) on the circle.
x
P (8, 15)
-17
O
17
Find an equation of the tangent at the point P.
Give your answer in the form y = ax + b where a and b are both
fractions with denominator 15.

Solution,

The equation of tangent to a circle with radius 'r' is given by:

x • x1 + y• y1= r^2

where (X1,y1) are point of intersection.

Therefore, the equation becomes:

8x+15y= (17)^2

8x+15y= 289

15y = -8x+289

y= -8/15 x +289/15

Hope this helps..

Good luck on your assignment..

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x