Someone help me pls, will give brainiest and high points

Step-by-step explanation:

Using sine rule on triangle ABC as re - shown in the attachment below to get side AC first we have;

∠A = 34°, BC = 164cm, ∠B = 27°, AC = ?

AC/sin 27° = BC/sin 34°

AC/sin 27° = 164/sin 34°

AC = 164 * sin 27° / sin 34°

AC = 74.45/0.5592

AC = 133.14 cm

To get the side 'a', we will use the trig ratio SOH CAH TOA on the right angled ACD.

According to SOH,

sin 61° = a/AC

a = ACsin61°

a = 133.14 * sin 61°

a = 116.45

a ≈ 117 cm

The marked side is approximately 117 cm

my acc plz

step-by-step explanation:

idc

step-by-step explanation:

idk