RE AINING: -
48:41
Question 40 of 50
Find the equation of the straight line that passes through
(2,-3) and perpendicular to the line 3x-2y+4=0
A. 2y-3x=0
B. 3y-2x+5=0
C. 3y+2x+5=0
D. 2y-3x-5=0
Question 41 of 50

C

Step-by-step explanation:

We start with the second line;

3x -2y + 4 = 0

3x + 4 = 2y

divide through by 2

3x/2 + 2 = y

Comparing this with standard form of y = mx + c

where m is slope

This means 3/2 is slope of the line

Since this line is perpendicular to the other line, then the product of their slopes is -1

3/2 * slope of second line = -1

Slope of second line = -1 divided by 3/2 = -2/3

We use the point slope form to find the equation of the other line

y-y1 = m(x-x1)

where m = -2/3 and (x1,y1) = (2,-3)

y-(-3) = -2/3 (x-2)

y + 3 = -2/3 (x -2)

3(y + 3) = -2(x-2)

3y + 9 = -2x + 4

3y + 5 = -2x

3y + 2x + 5 = 0

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is

not sure but it may be b, as i said i'm not sure.