The U-Drive Rent-A-Truck company plans to spend $88 million on 280280 new vehicles. Each commercial van will cost $25 comma 00025,000, each small truck $30 comma 00030,000, and each large truck $40 comma 00040,000. Past experience shows that they need twice as many vans as small trucks. How many of each type of vehicle can they buy?

400

Step-by-step explanation:

The computation is shown below:-

x = commercial vans

y = small trucks

z = large trucks

Therefore

x + y + z = 280 (i)

Given that

x = 2y (ii)

Now

$25,000 x + $30,000 y + $40,000 z = $88,000,000 (iii)

We know x = 2y already,

so in the first equation:

2y + y + z = 280

3y + z = 280

x = 280 - 3y

So, we will use this in the third equation

$25,000(2y) + $30,000y + $80,000(280-3y) = $88,000,000

$50,000y + $30,000y + $22,400,000 - $240,000y = $88,000,000

-$160,000y = -$65,600,000

y = 410

Putting in 410 in the second equation:

x = 2 × 410

= 810

and finally

= x - y

= 810 - 410

= 400

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

other answer is correct. i had used the radius of the radius somehow. a website: