A box of crayons has 12 different coloured crayons in it. 4 crayons are given to one child to play with, then another 4 are given to a second child to play with, and finally
the last 4 are given to a third child. In how many was can these crayons be
distributed?

  34,560

Step-by-step explanation:

Total crayons of different color = 12

Total children = 3

Each child will get 4 crayons.

Number of combinations of selecting r things out of n things =

The number of ways of selecting the first 4 crayons for first child =

Colors left = 12-4 =8

Now, the again selecting 4 colors out of 8 for second child =

Colors left =4

Number of ways of selecting 4 colors out of 4 for third child  =1

Total number of ways = 495 x 70 x 1 = 34650   [By fundamental principle of counting]

Hence, the total number of ways = 34,560.

answer: -8.2562234e+13