A student wants to estimate the mean score of all college students for a particular exam. First use the range rule of thumb to make a rough estimate of the standard deviation of those scores. Possible scores range from 300 to 2200. Use technology and the estimated standard deviation to determine the sample size corresponding to a 90% confidence level and a margin of error of 100 points. What isn't quite right with this exercise? The range. rule of thumb. estimate for the standard deviation. nothing.

See explanation below

Step-by-step explanation:

range = 2200 - 300 = 1900

To find standard deviation, we have:

standard deviation = range/4 = = 475

The range rule of thumb estimate for the standard deviation is 475

Given:

Standard deviation, = 475

Margin of Error, ME = 100

= 1 - 0.90 = 0.10

Za/2 = Z0.05 = 1.64

Find sample size, n:

n ≥

n ≥

n ≥ 60.68

≈ 61

Minimun sample size,n = 61

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol

the correct answer is $7.38

step-by-step explanation: