g A canyon is 1200 meters deep at its deepest point. A rock is dropped from the rim above this point. How long will it take the rock to hit the canyon floor

t = 15.6 s

Step-by-step explanation:

According to the kinematic equation:

  (1)

Where:

: is the final position = 1200 m

y₀: is the initial position = 0 m

V₀: is the initial speed = 0 m/s

g: is the gravity = 9.81 m/s²

t: is the time =?

From equation (1) we have:

Therefore, it will take 15.6 seconds to the rock to hit the canyon floor.

I hope it helps you!

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

answer: sine

step-by-step explanation: