Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

Step-by-step explanation:

The info given is:

number of students who said that they planned to work in a rural community

represent the sample size selected

the estimated proportion of students who said that they planned to work in a rural community

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by and . And the critical value would be given by:

The confidence interval for the mean is given by the following formula:  

Replpacing we got:

4.6875 pounds

step-by-step explanation:

b. 153 students do not participate in sports and seventy-five 12th graders were surveyed