Use the figure below to answer the question that follows: Intersecting triangles ACE and BDF. They intersect at points G, H, I, and J. Help! ASAP. Brainliest and 30 points! What must be given to prove that ΔBIJ ~ ΔBDF? A) segment GH is parallel to segment JI B) ∠ BIJ ≅ ∠ BFD C) segment JI is parallel to segment FD D) ∠ BGH ≅ ∠ BJI

Option C

Step-by-step explanation:

To prove that ΔBIJ ~ ΔBDF, we need to prove that their corresponding sides are proportional and to prove that their corresponding sides are proportional, we must say that JI is parallel to FD.

C) segment JI is parallel to segment FD

Step-by-step explanation:

If segments JI and FD are parallel, you will then have angles BIJ and BDF congruent by corresponding angles of parallel lines. Angle B is congruent to itself. Then you can us AA Similarity to prove triangles BIJ and BDF similar.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

i am not sure :

step-by-step explanation: