A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming all choices are available, how many different possible meals does the restaurant offer?

377 choices

Step-by-step explanation:

The following values were given in the question:

The restaurant offered

6 choices of appetizer

8 choices of main meal

5 choices of dessert.

We are also told in the question that the customer can choose to eat just one course, or two different courses, or all three courses.

Let us represent each choice by :

A = Appetizer = 6

B = Main meal = 8

C = Dessert = 5

a) The 3 choices together

ABC=6 × 8 × 5=240 choices

b) AB= Appetizer and Main meal

= 6 × 8 = 48 choices

c) AC= Appetizer and Dessert

= 6 × 5 = 30 choices

d) BC = Main meal × Dessert

= 8 × 5 = 40 choices

e) A,B,C = the customer having each of the choices only

Appetizer + Main meal + Dessert

= 6 + 8 + 5

= 19 choices

The number of possible meals is calculated as:

240 choices + 48 choices + 30 choices + 40 choices + 19 choices

= 377 choices

the correct answer is 5 6 and 7

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

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