Differentiate 1_x² over 1+x²

Dy/Dx=-4x/(1+x²)²

Step-by-step explanation:

The differential of 1_x² over 1+x²

First of all

1_x² over 1+x² = (1_x²) / (1+x²)

Let (1_x²) = u

Let (1+x²) = v

Differential = Dy/Dx

Dy/Dx of (1_x²) / (1+x²)

= (VDu/Dx -UDv/Dx)V²

u = (1-x²)

Du/Dx = -2x

(VDu/Dx) =(1+x²)(-2x)

V = 1+x²

Dv/Dx = 2x

UDv/Dx= (1-x²)(2x)

v² = (1+x²)²

Dy/Dx = ((1+x²)(-2x) - (1-x²)(2x))/(1+x²)²

Dy/Dx= ((-2x -2x³)-(2x-2x³))/(1+x²)²

Dy/Dx=( -2x -2x - 2x³ +2x³)/(1+x²)²

Dy/Dx=-4x/(1+x²)²

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.