What's the total surface area of a covered box with a length of 4 ft, a width of 3 ft, and a height of 6 ft? Question 17 options: A) 108 sq ft B) 38 sq ft C) 84 sq ft D) 96 sq ft

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A. 108 ft².

Step-by-step explanation:

Find the area of each face using the dimensions 4, 3 and 6. Remember, there are 6 total faces with 3 sets of congruent faces. The faces are rectangular, so the formula A = l × w will be used to solve for the area of each:

2(4 ·3) = 2(12) = 24 ft²

2(4· 6) = 2(24) = 48 ft²

2(3 · 6) = 2(18) = 36ft².

Add up the areas of the faces:

24 + 48 + 36 = 108 ft².

A) 108 sq ft

Step-by-step explanation:

SA = PH + 2LW

P = 2(L + W)

SA = 2(L + W)H + 2LW

SA = 2(4 ft + 3 ft)(6 ft) + 2(4 ft)(3 ft)

SA = 108 sq ft

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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step-by-step explanation: