Erica can run 1/6 start fraction, 1, divided by, 6, end fraction of a mile in a minute. Her school is \dfrac23 3 2 start fraction, 2, divided by, 3, end fraction of a mile away from her home. At this speed, how long would it take Erica to run home from school?

She runs 1/6 mile per minute.

School is 2/3 of a mile away from her home.

Rewrite 2/3 to have the same denominator as 1/6:

2/3 = 4/6

Divide distance by speed:

4/6 / 1/6 = 4/6 x 6/1 = 24/6 = 4

It will take her 4 minutes.

45

step-by-step explanation:

smple

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.