Factor by using the difference of two cubes a.
a³-64b³
b.
3x³-81y³z⁶
c.
16a³b³- 54c³d³

HELP ME PLEASE !!!

Step-by-step explanation:

a) a^3-64b^3

=(a)^3-(4b)^3

=(a-4b)(a^2+4ab+16b^2)

b) 3x^3-81y^3z^6

=3(x^3-27y^3z^6)

=3{(x)^3-(3yz^2)^3}

=3(x-3yz^2)(x^2+3xyz^2+9y^2z^4)

c)16a^3b^3-54c^3d^3

=2(8a^3b^3-27c^3d^3)

=2{(2ab)^3-(3cd)^3

=2(2ab-3cd)(4a^2b^2+6abcd+9c^2d^2)

hope u got!!

step-by-step explanation: