X= 3y-5 2x + 12y = -4
This is a system of equations can somebody solve it you can use any method

x = -4, y = 1/3

Step-by-step explanation:

=> x = 3y-5        (Equation 1)

=> 2x+12y = -4  (Equation 2)

Putting (1) in (2)

=> 2(3y-5)+12y = -4

=> 6y-10+12y = -4

=> 18y = -4+10

=> 18y = 6

Dividing both sides by 18

=> y = 6/18

=> y = 1/3

Putting y = 1/3 in Equation 1

=> x = 3(1/3)-5

=> x = 1-5

=> x = -4

the answer would be c:   ax + b = ax + c

step-by-step explanation: