If A, dollars are invested at annual interest rate r, compounded monthly, then after years the account will have grown to
121
A(t) = 40 (1
10 (1 + )"
12
If $2000 is placed into an account eaming 12% annual
interest, compounded monthly, how much will it grow to after
15 years?

  $11,991.60

Step-by-step explanation:

An appropriate formula is ...

  A = P(1 +r/n)^(nt)

where r is the annual rate, n is the number of time per year interest is compounded, and t is the number of year. P is the principal invested.

Filling in the given numbers, we have ...

  A = $2000(1 +0.12/12)^(12·15) = $2000(1.01^180) ≈ $11,991.60

The account balance after 15 years will be $11,991.60.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.