In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD = °.

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63°

Step-by-step explanation:

We are told in the above question that for parallelogram ABCD, ∠ABD=83° and ∠BDA=34°.

To get the above angles, parallelogram ABCD was split into two triangles by a diagonal given us ∆ABD and ∆BCD

Remember that angles in a triangle = 180°

∆ABD has ∠ABD=83°, ∠BDA=34° and ∠DAB

180° = ∠ABD + ∠BDA+ ∠DAB

180° = 83° + 34° + ∠DAB

∠DAB = 180°-117°

=63°

Since ∆ABD and ∆BCD are similar triangles because they are from one parallelogram,

∠DAB = ∠BCD

= 63°

Therefore, the measure of the angle BCD is 63°.

idk

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.