Taymoor is going to apply for two different jobs. He estimates that the probability of getting job Ais 0.3 and the probability of getting job B is 0.4 The job offers will be made independently. What is the
probability that he gets at least one job?
0.58
0.82
0.7
0.12

0.58

Step-by-step explanation:

The probability that Taymoor gets at least one job is a  sum of probabilities of 3 events:

1.He gets Job 1 (P(1.yes)= 0.3) and doesn't get the job 2 (P(2.not)=1-0.4=0.6)

P(1.yes,2.not)=P(1.yes)*P(2.not)=0.3*0.6=0.18

2. He doesn't get job1 (P(1.not)= 1-03=0.7 ) and gets job2(P2.yes)=0.4)

P(1.not,2.yes)=P(1.not)*P(2.yes)=0.7*0.4=0.28

3. He gets  job1 (P(1.yes)= 0.3 ) and gets job2(P2.yes)=0.4)

P(1.yes,2.yes)=P(1.yes)*P(2.yes)=0.3*0.4=0.12

The resulted probability is P(gets job)= 0.18+0.28+0.12=0.58

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3