Find the slope-intercept form of the line with slope 6 that passes through the point (3,5).

y=6x-13

Step-by-step explanation:

Since we are given a point and a slope, we can use the slope intercept formula.

where (x1, y1) is a point and m is the slope.

We know that the slope is 6 and the point is (3,5). Therefore,

x1= 3

y1= 5

m=6

Substitute these into the formula.

Distribute the 6. Multiply each term inside the parentheses by the number outside the parentheses.

We want to find the slope-intercept form, or y=mx+b. Therefore, we must get y by itself.

5 is being subtracted from y. The inverse of subtraction is addition. Add 5 to both sides.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true