To determine if loans from bank 1 are less affordable than loans from bank 2, the mean loan rate of the two competing banks is compared. Twenty-five loans are randomly sampled from each bank and the loan rates are recorded. Both populations have normal distributions with unknown standard deviations. State the null and alternative hypotheses.

Step-by-step explanation:

The null hypothesis is an smoothies l that states that there is no difference or association between populations while the alternative hypothesis always aims to prove otherwise.

In this case study, the null hypothesis is that loans from bank 1 are more affordable than loans from bank 2. Bank 1 average loan >= bank 2 average loan.

Alternative hypothesis: loans from bank 1 are less affordable than loans from bank 2

Bank 1 average loan < bank 2 average loan.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: