What is the difference? x+5/x+2-x+1/x2+2x

Question

x+5/x+2 - x+1/x²+2x

= (x² - 4x - 1)/[x (x+2)]

= (x² - 4x - 1)/[x² + 2x]

Step-by-step explanation:

x + 5/x + 2 - x + 1/x² + 2x

We factorise the second denominator to give us :

x + 5/x + 2 - x + 1/x(x + 2)

We find the L.C.M of both denominators which is x(x+2).

[x(x + 5)-(x + 1)] / (x (x + 2))

Expand the bracket

=[x² +5x - x -1] / [x (x + 2)]

=(x² - 4x - 1) / [x (x + 2)]

= (x² - 4x - 1)/ [x (x + 2)]

= (x² - 4x - 1) / [x² + 2x]

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

do you have an easier question cause this shh is hard like theheck

step-by-step explanation: