You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?

  20  

Step-by-step explanation:

Once you give 1 candy to each of the 4 kids, you will have 3 remaining. The number of ways those can be distributed to 4 kids is given by ...

  (n+k-1)C(n)

where n is the number of candies, and k is the number of kids. "aCb" is the number of ways a can be taken b at a time:

  aCb = a!/(b!(a-b)!)

For n=3 and k=4, this is ...

  (3+4-1)C(3) = 6C3 = 6!/(3!·3!) = 20

There are 20 ways to distribute 7 candies to 4 kids so that each kid receives at least one.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x