A man starts walking north at 5 ft/s from a point P. Five minutes later a woman starts walking south at 7 ft/s from a point 500 ft due east of P. At what rate are the people moving apart 15 min after the woman starts walking? (Round your answer to two decimal places.) ft/s

11.97 ft/s

Step-by-step explanation:

Let x be the  vertical distance of man from point P and y be the  vertical distance of woman from point P

Total time=5+15 =20  mins

Distance traveled by man in 20 min

a=

1 min=60 s

Distance traveled by Woman in 15 min

z=500  ft

x+y=6000+6300=6900 ft

Using Pythagoras formula

Differentiate w.r.t t

the graph on the bottom right