The sugar content of the syrup in canned peaches is normally distributed. A random sample of n=25 cans yields a sample standard deviation of s=6.9 milligrams. Construct a 99% one-sided lower confidence bound for the population variance.

99% one-sided lower confidence bound = 26.77

Step-by-step explanation:

We have to calculate a 99% one-sided lower confidence bound for the population variance.

The sample size is n=25.

The degrees of freedom are then:

The critical value of the chi-square for this confidence bound is:

Then, the lower confidence bound can be calculated as:

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

nothjing

step-by-step explanation: