There are crows and groundhogs in a field. All of them together have 15 heads and 40 legs. How many of each animal are in the field?

idk

Step-by-step explanation:

I'm going to do some deep research to find the answer. One sec

There are 5 groundhogs and 10 crows.

Step-by-step explanation:

Ok, so there are 15 animals and 40 legs. So, groundhogs have 4 legs while crows have 2. Lets say x= our groundhog legs, and y= our crow legs. Our equations are 4x+2y=40 and x+y=15. Now that we have the equations needed we just have to solve them. Now we subtract the two equations from each other. So, this would get,

                                                                            4x+2y=40

                                                                           -   x+  y=15

                                                                               3x+y=25.

Now we need to subtract x to the other side. So, now we have y=25-3x. The only solution to this problem is (5,10). 25-3(5)=25-15=10. To check this lets put them into our original equations, 4x+2y=40 and x+y=15. So, 4(5) + 2(10)=20+20=40, and 5+10=15! So there's your answer.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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