There are 12 donuts in a box, and Claire at 2. Approximately what percent of the donuts remain in the box? (Round to the nearest whole number.)

83% remains in the box

Step-by-step explanation:

Here, we are interested in calculating the percentage of donuts remaining in the box.

From the question, we are told that 2 was eaten, the number of donuts left = 12-2 = 10 donuts

The percentage of donuts left would be;

Number of donuts left/Total no of donuts * 100%

= 10/12 * 100 = 83.33

Which is 83% to the nearest whole number percentage

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !