Solve the system of equations for the variables: 5x+2y=13 x+2y=9

x = 1

y = 4

Step-by-step explanation:

5x + 2y = 13

x + 2y = 9

Add both equations.

6x + 4y = 22

Solve for x.

6x = 22 - 4y

x = 22/6 - 4/6y

Put x as 22/6 - 4/6y in the second equation and solve for y.

22/6 - 4/6y + 2y = 9

-4/6y + 2y = 9 - 22/6

4/3y = 16/3

y = 16/3 × 3/4

y = 48/12

y = 4

Put y as 4 in the first equation and solve for x.

5x + 2(4) = 13

5x + 8 = 13

5x = 13 - 8

5x = 5

x = 5/5

x = 1

x = 1, y = 4

Step-by-step explanation:

5x+2y = 13

x+2y = 9

Subtracting both equations

=> 5x+2y-x-2y = 13-9

=> 4x = 4

=> x = 1

Now, Putting x = 1 in the first equation

=> 5(1)+2y = 13

=> 2y = 13-5

=> 2y = 8

=> y = 4

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2