Find the measures of the angles of the ∆ABC if m∠A : m∠B : m∠C = 2:3:4.

m∠A = 2x = 2*20 = 40

m∠B = 3x = 3*20 = 60

m∠C= 4x = = 4*20 = 80

Step-by-step explanation:

we know sum of angles of triangle is 180 degrees

given

m∠A : m∠B : m∠C = 2:3:4

let the angle be

m∠A = 2x

m∠B = 3x

m∠C= 4x

we have taken such angle by applying rule of indices where

a:b:c = ax:bx:cx

which means that if we multiply all term of ratio by same number ratio remains same

thus,

2x+3x+4x = 180

9x = 180

x = 180/9 = 20

Thus,

m∠A = 2x = 2*20 = 40

m∠B = 3x = 3*20 = 60

m∠C= 4x = = 4*20 = 80

true? is that what you're asking or do you mean something else?

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step-by-step explanation: