The function h(t) = 2.3 + 50t - 1.86t^2 models the height of an arrow shot from a bow on Mars, where h(t) is the height in metres and t is time in seconds. How long does the arrow stay in flight?

The arrow stay in flight for 26.92 seconds

Step-by-step explanation:

We are given that  the height of an arrow shot from a bow on Mars is modeled by equation:

Where h(t) is the height of arrow

t is the time in seconds

Now we are supposed to find How long does the arrow stay in flight?

Substitute h(t)=0

So,

t=-.04 , 26.92

Since the time cannot be negative

So,the arrow stay in flight for 26.92 seconds

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6