Let g be the function defined by g(x) = − 1 2 x + 5 if x < 6 x − 6 if x ≥ 6. Find g(−6), g(0), g(6), and g(12). g(−6) = g(0) = g(6) = g(12) =

  g(-6) = 8; g(0) = 5; g(6) = 0; g(12) = 6

Step-by-step explanation:

We assume your function definition is ...

For each given value of x, determine which segment applies, then evaluate.

For x = -6 and for x = 0, the first segment applies:

  g(-6) = (-1/2)(-6) +5 = 3 +5 = 8

  g(0) = (-1/2)(0) +5 = 5

For x = 6 and x = 12, the second segment applies:

  g(6) = (6) -6 = 0

  g(12) = (12) -6 = 6

In summary, ...

  g(-6) = 8; g(0) = 5; g(6) = 0; g(12) = 6

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)