Which system of equations has no solutions? 1. x-3y+3z=-4
2x+3y-z=15
4x-3y-z=19

2. 3x-3y+4z=6
-3x+3y-4z=-6
6x-6y+8z=12

3. -2a-4b+6c=5
-a+3b-2c=-1
a+2b-3c=1

4. x+y=9
y+z=7
x-x=2

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

my answer got deleted but it's a

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

bdhfnfhjffjkfjfjfjjf