Write an equation in point-slope form for each line (If possible please show work)

Hey there! :)

x = 1/2(y -3)

Step-by-step explanation:

Begin by finding the slope using the slope formula:

Plug in the coordinates:

Simplify:

Recall that point-slope form is:

Plug in the slope and coordinates into the equation:

(x - 0) = 1/2(y - 3)

x = 1/2(y -3)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

you can use a^2+ b^2=c^2