Rectangle LMNO has vertices L(–4,6), M(–1,6), N(–1,2), and O(–4,2). Suppose you first reflect this rectangle across the y-axis. Then, translate it down four units and to the left one unit. Where are the corresponding vertices L′M′N′O′ located?

L'(3, 2)

M'(0, 2)

N'(0, -2)

O'(3, -2)

Step-by-step explanation:

Vertices of a rectangle LMNO are L(-4, 6), M(-1, 6), N(-1, 2) and O(-4, 2).

If a point (x, y) is reflected across y-axis, rule to be followed,

(x, y) → (-x, y)

After reflection across y-axis new ordered pairs will be,

L(-4, 6)   → L"(4, 6)

M(-1, 6)   → M"(1, 6)

N(-1, 2)   → N"(1, 2)

O(-4, 2)  → O"(4, 2)

Then these points were translated 4 units down and 1 unit left,

Rule to be followed for the translation will be,

(x'', y'') → [(x' - 1), (y' - 4)]

By this rule vertices of the rectangle after translation will be,

L''(4, 6) → L'(3, 2)

M''(1, 6) → M'(0, 2)

N''(1, 2) → N'(0, -2)

O''(4, 2) → O'(3, -2)

d

step-by-step explanation:

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°