Find the focus and the directrix of the parabola with the equation y = 1∕4(x – 6)2+ 5 Question 16 options:

A)

Focus = (5,–6), directrix is y = –7

B)

Focus = (6,6), directrix is y = 4

C)

Focus = (6,–6), directrix is y = –4

D)

Focus = (–5,6), directrix is y = –4

B)

Focus = (6,6), directrix is y = 4

Step-by-step explanation:

A parabola is the locus of a point that is equidistant from a fixed line (known as directrix) and a fixed point (known as focus).

The equation of a parabola in vertex form is given as:

It can be further simplified to:

The directrix of this parabola is given at line y = k - p and the focus is at (h, k + p)

Given that:

Comparing (x-6)² = 4(y-5) with (x-h)² = 4p(y-k), It can be gotten that h = 6, p =1 and k = 5

The directrix of this parabola is given at line y = k - p = 5 - 1 = 4 and the focus is at (h, k + p) =  (6, 5+1) = (6, 6)

Focus = (6,6), directrix is y = 4

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.