Consider the function ƒ(x) = (x + 1)2 – 1. Which of the following functions stretches ƒ(x) vertically by a factor of 4? Question 5 options:

A)

ƒ(x) = 4(x + 1)2 – 1

B)

ƒ(x) = 4(4x + 1)2 – 1

C)

ƒ(x) = (1∕4x + 1)2 + 3

D)

ƒ(x) = 1∕4(x + 1)2 – 4