Write the equation of the line that passes through the points (8, –1) and (2, –5) in standard form, given that the point-slope form is y + 1 = (x – 8). x + y =

  2x -3y = 19

Step-by-step explanation:

For the two points (8, -1) and (2, -5), the two-point form of the equation of a line is ...

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (-5-(-1))/(2 -8)(x -8) +(-1)

  y = -4/-6(x -8) -1

  3y = 2x -16 -3 . . . . multiply by 3

  2x -3y = 19 . . . . . . rearrange to standard form

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The point-slope form is y +1 = 2/3(x -8). It helps to have all the numbers.

2x + -3y = 19

Step-by-step explanation:

I promise

b) well because you get well

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm