What are the coordinates of the point that partitions AB according to the part-to-part ratio 4:3?

(-1,0)

Step-by-step explanation:

Here, our interest lies in finding the coordinates that splits the points (-5,-8) and (2,6) in the ratio 4:3. Let the point that does the splitting be called point P

The section formula is used here and the point we are having would be;

P = (mx2 + nx1)/(m+n) , (my2 + ny1)/(m + n)

From the question;

m = 4 and n = 3

x1 = -5, y1 = -8

x2 = 2 , y2 = 6

Plugging these values in the equation above, we have;

P = [4(2) + 3(-15)](3+4), [4(6) + 3(-8)]/(3+4)

P = (8-15)/7, (24-24)/7

= -7/7, 0/7

= (-1, 0)

The coordinates of point P is (-1,0)

c

step-by-step explanation:

at least i think its

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50