. (01.05) 1.Write the equation of a line with a slope of 4 and a y-intercept of −3. (2 points) A- 4x + y = −3 B-4x − y = −3 C- y = −3x + 4 D- y = 4x − 3 2. (01.05) Write the equation of the line that passes through (−1, 5) and has a slope of 3 in point-slope form. (2 points) A- x + 1 = 3(y − 5) B- x − 5 = 3(y + 1) C- y − 5 = 3(x + 1) D- y + 1 = 3(x − 5) 3. (01.05) Write the equation of the line that passes through (1, 5) and (−2, 14) in slope-intercept form. (2 points) A- y = 3x + 2 B- y = 3x + 8 C- y = −3x − 2 D- y = −3x + 8

The correct option is 4.

Step-by-step explanation:

Step-by-step explanation:

The slope intercept form of a line is

                  (1)

where, m is slope and b is y-intercept.

We need to find the equation of line whose slope is 4 and y-intercept is -3.

Substitute m=4 and b=-3 in equation (1), to find the equation of required line.

The equation of required line is y=4x-3.

Therefore the correct option is 4.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11