What is the period of the function y= 3/2 cot(3/5x) +5? A. Pi/5 units

B. 3pi/5 units

C. 2pi/3

D. 5pi/3

D; 5pi/3 units

Step-by-step explanation:

Here, we want to find the period of the function;

y = 3/2 cot (3/5x) + 5

By definition, the period of a function is the interval between two matching points in the function.

Let’s say it is the distance between two peaks, crests, etc on a function.

To find the value of the period. We shall standardize the function.

What this means is that we shall be writing the function in the standard form.

The standard form is as follows;

f(x) = A trig(Bx -C) + D

Where trig refers to the accompanying trigonometric function in question.

Comparing this standard form with our question, we can see that;

A is 3/2

B is 3/5

C is 0

D is 5

Now for cot and tan functions, we shall need to divide pi by the absolute value of B

Thus we have; pi divided by 3/5 which gives 5pi/3 units

D. 5pi/3, period is the distance between the repetition of a function.

Step-by-step explanation:

im sorry but no. i just need to answer for 50 poonts oof

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: