If y varies inversely as x and y=6 when x=8 find y when x=7

y = 5  1/4

Step-by-step explanation:

For direct or inverse variation relation

relation between two variable and y can be expresses in form of

y = kx  where k is constant of proportionality .

Only thing happens in inverse relation is that when x increases then y decreases and vice versa. That is care by constant of proportionality

Thus, let the inverse relation be

y = kx

given

when y = 6 then x = 8

we will plug this value in y = kx

6 = k*8

=>k = 6/8 = 3/4

Thus,

relation is

y = 3/4 x

we have to find y when x = 7 ,

lets put x = 7 in y = 3/4 x

y = 3/4 *7 = 21/4 = 5 1/4

Thus, when x = 7 then y = 5 1/4

if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it