Jim Gym, a high school basketball coach, wants to analyze the height of the boys at his school. He knows their height is normally distributed so he can use the standard normal distribution. He measures the height of 100 randomly selected boys. Next, he calculates the mean and standard deviation of their heights. The mean is 66 inches and the standard deviation is 5 inches. Jim uses the normal distribution table to calculate the number of boys in each segment of the distribution.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

2

step-by-step explanation:

x = 3 ± √(5+y)