Which of the following equations is of a parabola with a vertex at (-6, 0)? y = x^2 + 6 y = ( x + 6) ^2 y = x^2 - 6 y = ( x - 6) ^2

Hey there! :)

y = (x + 6)².

Step-by-step explanation:

Recall that the transformations form of a parabola is:

y = ±a (b(x-h))+k where (h, k) are the coordinates for the vertex.

In this instance, the parabola has a vertex at (-6, 0). Therefore:

h = -6, k = 0.

The only equation given that satifies these conditions are:

y = (x + 6)².

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy