Use differentials to estimate the amount of tin in a closed tin can with diameter 12 cm and height 11 cm if the tin is 0.04 cm thick.

16.65 cm³

Step-by-step explanation:

Given that :

the diameter of the closed tin can = 12 cm

the height of the closed tin can = 11 cm

The thickness of the closed tin can  = 0.04 cm

The main task required to be carried out is to use differentials to estimate the amount of tin in a closed tin can.

We all know that the volume of a tin can =

The differential of the volume   is :

Differentiating V  with respect to r; we have:

Differentiating V with respect to h ; we have:

Hence; the estimate of the amount of tin in a closed tin can is:

=

=

=

where;

dr = increase in radius = 0.04cm (since thickness of the radius = 0.04 cm)

dh = increase in the height = 0.04 + 0.04 = 0.08

= 16.65 cm³

Hence; the amount of tin in a closed tin can  is = 16.65 cm³

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct