A standard fair dice is rolled twice. What is the probability of getting an odd number on the first roll and any number except 4 on the other?

Let,O and P be the events of getting odd number and any other number except 4 respectively.

n(S)=6

O=(1,3,5) so, n(O)=3

P=(1,2,3,5,6) so, n(P)=5

So,probability of getting an odd number and any other number except 4 will be

n(O)/n(S) × n(P)/n(S)

=3/6 × 5/6

=5/12

May be it's the answer I guess. Hope you're clear with it:-)

b

step-by-step explanation:

calculate the scale factor as the ratio of corresponding sides, image to original, that is

scale factor = = = = 1

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step-by-step explanation: