Two events A and B are such that P(A) = 0.6, P(B) = 0.2 and P(B A) = 0.22. Calculate probability that:
i) Both of the events occur, P(A n B)
ii) Either A or B or both occur, P(AUB)
(
iii) A occurs given that B occurs, P(A|B)
Na

Step-by-step explanation:

hello

P(B/A)=P(A∩B)/P(A)

so P(A∩B)=P(A)P(B/A)=0.6*0.22=0.132

P(A∪B)=P(A)+P(B)-P(A∩B)=0.6+0.2-0.132=0.668

P(A/B)=P(A∩B)/P(B)=0.132/0.2=0.66

hope this helps

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.