What are the chances of choosing a black marker out of a bag containing 3 red markers, 5 blue markers, 3 yellow markers, and 4 black markers? What is the probability of choosing two black markers if the first marker is put back before the second is drawn?

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Step-by-step explanation:

It is given that,

Number of red markers = 3

Number of blue markers = 5

Number of yellow markers = 3

Number of black markers = 4

Total markers = 3 + 5 + 3 + 4 = 15

Probability of getting a black marker is

Probability of choosing two black markers if the first marker is put back before the second is drawn, is

Required probability  

Therefore, the  probability of choosing two black markers if the first marker is put back before the second is drawn, is .

do i do it on a graph?

step-by-step explanation:

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76