Find the distance between y=−56x−1 and the parallel line that passes through (6,−4). Round your answer to the nearest tenth.

The distance between the two parallel lines is y = -56·x - 1 and the parallel line that passes through the point (6, -4) is 5.91 units

Step-by-step explanation:

The parameters given are;

Equation of the line y = -56·x - 1

The point the parallel line passes = (6, -4)

Given that the slope and intercept form of a line is y = m·x + c

Where:

m = The slope = (y₂ - y₁)/(x₂ - x₁)

c = y- intercept

Comparing y = m·x + c with y = -56·x - 1 gives;

m = -56, c = -1

The equation of the parallel line is presented as follows

y - (-4) = (x - 6)(-56)

y = -56x +336 - 4 = -56x + 332

The formula for the distance, d, between two parallel lines is given by the following relation;

Where:

c₁ and c₂ are the coordinates of the point constant y-intercept in both equations when the line equation is written as follows;

y = -56·x - 1 → y + 56·x + 1 = 0

a and  b are the x and y coefficients

Which gives;

which gives

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x